Here decimal to binary/octa/hexa decimal conversions are shown.

Algorithm is simple provided we should make use of the stack (stack implementation) to put the coefficients.

```public class DecimalConversion {
TNStack st = new TNStack(30);
private static HashMap<Integer, String> hm = new HashMap<Integer, String>();

/**
* converts number to given base
* @param number
* @param base
*/
public void decimalToXXXConversion(int number, int base) {
System.out.println("Number "+number+" in base "+base+" is: ");
while(number>0) {
st.push(number%base);
number = number/base;
}

while(!st.isEmpty()) {
int n = st.pop();
if(n>9) {
String str = hm.get(n);
System.out.print(str);
} else {
System.out.print(n);
}
}
System.out.println();
}

/**
* @param args
*/
public static void main(String[] args) {
DecimalConversion dc = new DecimalConversion();

// decimal to binary conversion
dc.decimalToXXXConversion(100, 2);

// decimal to octal conversion
dc.decimalToXXXConversion(100, 8);

hm.put(10, "A");
hm.put(11, "B");
hm.put(12, "C");
hm.put(13, "D");
hm.put(14, "E");
hm.put(15, "F");
dc.decimalToXXXConversion(10012, 16);
}
}
```

Output:
Number 100 in base 2 is:
1100100
Number 100 in base 8 is:
144
Number 10012 in base 16 is:
271C

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