decimal to binary/octa/hexadecimal conversion

Here decimal to binary/octa/hexa decimal conversions are shown.

Algorithm is simple provided we should make use of the stack (stack implementation) to put the coefficients.

public class DecimalConversion {
	TNStack st = new TNStack(30);
	private static HashMap<Integer, String> hm = new HashMap<Integer, String>();
	
	/**
	 * converts number to given base
	 * @param number
	 * @param base
	 */
	public void decimalToXXXConversion(int number, int base) {
		System.out.println("Number "+number+" in base "+base+" is: ");
		while(number>0) {
			st.push(number%base);
			number = number/base;
		}
		
		while(!st.isEmpty()) {
			int n = st.pop();
			if(n>9) {
				String str = hm.get(n);
				System.out.print(str);
			} else {
				System.out.print(n);
			}
		}
		System.out.println();
	}
	
	/**
	 * @param args
	 */
	public static void main(String[] args) {
		DecimalConversion dc = new DecimalConversion();
	
		// decimal to binary conversion
		dc.decimalToXXXConversion(100, 2);

		// decimal to octal conversion
		dc.decimalToXXXConversion(100, 8);
				
		// decimal to hexadecimal conversion
		hm.put(10, "A");
		hm.put(11, "B");
		hm.put(12, "C");
		hm.put(13, "D");
		hm.put(14, "E");
		hm.put(15, "F");
		dc.decimalToXXXConversion(10012, 16);	
	}
}

Output:
Number 100 in base 2 is:
1100100
Number 100 in base 8 is:
144
Number 10012 in base 16 is:
271C