# decimal to binary/octa/hexadecimal conversion

March 12, 2013 Leave a comment

Here decimal to binary/octa/hexa decimal conversions are shown.

Algorithm is simple provided we should make use of the stack (stack implementation) to put the coefficients.

public class DecimalConversion { TNStack st = new TNStack(30); private static HashMap<Integer, String> hm = new HashMap<Integer, String>(); /** * converts number to given base * @param number * @param base */ public void decimalToXXXConversion(int number, int base) { System.out.println("Number "+number+" in base "+base+" is: "); while(number>0) { st.push(number%base); number = number/base; } while(!st.isEmpty()) { int n = st.pop(); if(n>9) { String str = hm.get(n); System.out.print(str); } else { System.out.print(n); } } System.out.println(); } /** * @param args */ public static void main(String[] args) { DecimalConversion dc = new DecimalConversion(); // decimal to binary conversion dc.decimalToXXXConversion(100, 2); // decimal to octal conversion dc.decimalToXXXConversion(100, 8); // decimal to hexadecimal conversion hm.put(10, "A"); hm.put(11, "B"); hm.put(12, "C"); hm.put(13, "D"); hm.put(14, "E"); hm.put(15, "F"); dc.decimalToXXXConversion(10012, 16); } }

**Output:**

Number 100 in base 2 is:

1100100

Number 100 in base 8 is:

144

Number 10012 in base 16 is:

271C

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